We shall now graph the line 3x+5y-15 = 0 and calculate its properties, Notice that when x = 0 the value of y is 3/1 so this line "cuts" the y axis at y= 3.00000, When y = 0 the value of x is 5/1 Our line therefore "cuts" the x axis at x= 5.00000, Slope is defined as the change in y divided by the change in x. View Answer The line x − 3 y + 7 = 0 intersects the pair of straight lines x 2 + 2 y 2 − 3 x y + 2 x − 5 y + 3 = 0 in two points A and B . 1 0. Como. slope = -3/5. Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. asked Feb 27, 2019 in Class X Maths by priya12 (-12,630 points) coordinate geometry. we can use this to solve for C. 3(-5) + C = 0-15 + C = 0. 8 Answers. 6.4 19-45 odds ; Due Wednesday 1/14/04 ; 6.5 13-25 … MarcPearce MarcPearce Answer: It's a straight line Step-by-step explanation: The line has a slope of 3/5 and a y-axis crossing of -3 New questions in Mathematics. 1 0. esperism. Slope = 3/5, so perpendicular slope = -5/3. slope of a line parallel = -3/5. Plotting these points and drawing a line through them gives us a graph that should look like: Answer: 1 question Find 5 solutions for the linear equation 3x-5y=15, and plot the solutions as points on a coordinate plane. A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. Which graph represents -3x+5y=-15? Relevance. 3x + 5y = 18. Given that two lines are perpendicular, MarcPearce MarcPearce Answer: It's a straight line Step-by-step explanation: The line has a slope of 3/5 and a y-axis crossing of -3 New questions in Mathematics. Take an arbitrary point on one of the lines and find its distance from the other line. (D) a circle Q.5 m, n are integer with 0 < n < m. A is the point (m, n) on the cartesian plane. Answer to: Use the intercepts to graph the equation 3x-5y=15. 4x-3y = 17 .Answer. What is the midpoint of the line segment between the two points (-3, 2) and (4, 0)? 105. Such an equation is usually written y=mx+b ("y=mx+c" in the UK). What is the solution to the system of equations 5x + 5y = 15 and 2x + 2y = 6? The equation is, ax + by + c = 0; so, in intercept form it … 9 Graphing equations in different forms. Answer: 1 question Find 5 solutions for the linear equation 3x-5y=15, and plot the solutions as points on a coordinate plane. A straight line l 1 with equation x-2y+10=0 meets the circle with equation x 2 + y 2 = 1 0 0 at B in the first quadrant. 5y = - 3x + 15. y = (-3/5) x + 3. m = - 3/5 is slope of line . Q.12 A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in - (1) 1st, 2nd and 4th quadrants (2) 1st and 2nd quadrants (3) 4th quadrants (4) 1st quadrants Ans. (C.B.S.E. Q.17 A is a point on either of two lines y + 3 x = 2 at a distance of 4 3 units from their point of intersection. Question 12. x – 2y = 5 3x – 6y = 15 Solution: x – 2y = 5 x = 5 + 2y Substituting some different values of y, we get corresponding values of x as shown below: Now plot these points on the graph and join them 3x – 6y = 15 => 3x = 15 + 6y x = \(\frac { 15 + … Plug in . Q.17 A is a point on either of two lines y + 3 x = 2 at a distance of 4 3 units from their point of intersection. Q.16. 2. x+y=0, 3x-y+2=0, y+1=0, y=0. Given a straight line x cos 30° + y sin 30° = 2. 4x-20 = 3y-3. A straight line passes through the point (3, 2) and the portion of this line, intercepted between the positive axes, is bisected at this point. x=5. A point which is equidistant from both the axes lies on either y = x and y = -x. Let the equation of a line is 3x + 5y = 15 and a point P on this line is equidistant from x and y axis. Write down the equation of the line perpendicular to 3x +8y = 12 and passing through the point (-1, -2). Find the distance of the point (4, 5) from the straight line 3x − 5y + 7 = 0. Your straight line is 8x - 5y - 15 = 0. Find the distance between the origin and the straight line 12x-5y+39=0. In which quadrant the point P lies? C is the Such an equation is usually written y=mx+b ("y=mx+c" in the UK). Answer 14. Take a point P on the left of y-axis such that the distance of point P from the y-axis is 2 units. Find the equation of the straight line passing through the point (2, 1) and bisecting the portion of the straight line 3x − 5y = 15 lying between the axes. If you need to find a line given two points or a slope and one point, use line … Do the following to find the point where the two lines INTERSECT(where they cross). Solution: Given points, A (3, -4) and B (-2, 1) By section formula, the co-ordinates of the point P which divides AB in the ratio 1: 3 is given by = (7/4, -11/4) = (x 1, y 1) … QED. What is the general form of the line y = - x + 1? asked Feb 28, 2019 in Class X Maths by aditya23 ( -2,145 points) Solution Show Solution The equation of the line in intercept form is \[\frac{x}{a} + \frac{y}{b} = 1\]. Given a straight line with equation coefficients as a, b & c(ax + by + c = 0), the task is to find the area of the triangle formed by the axes of co-ordinates and this straight line.. we can use this to solve for C. 3(-5) + C = 0-15 + C = 0. (The change in y is sometimes referred to as "RISE" and the Slope is m = RISE / RUN), Beginning Algebra Tutorial 11: Simplifying Algebraic Expressions. Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. so in the given line: -3x + 5y - 15 = 0. sub in y = 0 to find the x-intercept: -3x - 15 = 0. x = -5. thus, the point (-5 , 0) will be on the desired line. 2 Answers. 5y + 15 = -3x + 33. 1. Knowledge required: General equation of a line is y=mx+c. Comparing ax + by + c = 0 and 3x − 5y + 7 = 0, we get: We note that for x=0, the value of y is 3.000 and for x=2.000, the value of y is 1.800. Find the equation of a straight line passing through the intersection of 2x + 5y – 4 = 0 with x-axis and parallel to the line 3x – 7y + 8 = 0. of required line is:- y-1= 4/3.(x-5). Answer Save. Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. asked Feb 27, 2019 in Class X Maths by priya12 ( -12,630 points) coordinate geometry Some important points to remember #Straight Line A straight line is a curve , such that every point on the line segment joining any two points on it lies on it. 5y=3x … Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students. For any pair of mirror points on the given line, the midpoints of their tangent chord line are also mirror points. 1 … A point on the straight line, 3x + 5y = 15 which is equidistant from the coordinate axes will lie only in -, Correct option (2) 1st and 2nd quadrants. Find (i) the gradient of EF (ii) … Which graph represents -3x+5y=-15? Select two values, and plug them into the equation to find the corresponding values. From above graph, we can see that, Point A (1, 4) is already plotted on the graph, and a point of intersection of two intersecting lines. harry m. Lv 6. Download this lesson as PDF:-Straight Lines PDF. Show that the straight lines 2x-3y=6 and 4x-6y = = 25 are parallel, and find the distance between them. Find the equation of the straight line perpendicular to 5x – 2y = 8 and which passes through the mid-point of the line segment joining (2, 3) and (4, 5). 3x + 5y = 15 equation of straight line x = y 8x = 15 … In the special case where the two mirror points become one on the symmetry line, so do their chord lines, which become parallel to the given line The slope of the line is the value of , and the y-intercept is the value of . First, get the original line in y = mx + b form: 5y = 3x - 3. y = 3/5 x - 3/5. Question By default show hide Solutions. 3=3/5x. A straight line is passing through the point (1, 2) and parallel to the line y = 3x + 1 . Slope-intercept form y mx b ; Use the y-intercept and the slope. where the line crosses the Y axisThe X and Y intercepts and the Slope are called the line properties. asked Feb 28, 2019 in Class X Maths by aditya23 ( -2,145 points) [2] CAREER POINT CAREER POINT Ltd., CP Tower, IPIA, Road No.1, Kota (Raj. (a) Solution. Must show work. Multiply … Choose to substitute in for to find the ordered pair. (C) a straight line with slope 1 and x intercept 3. (3) Solution. Hint. Find the Distance of the Point (4, 5) from the Straight Line 3x − 5y + 7 = 0. C = 15. the desired line is : 3x + 4y + 15 = 0 - the answers to estudyassistant.com x and y intercept of straight line 3x-5y=15? Yes, the line 3x = y + 1 is the bisector. Use the slope and a given point to substitute for and in the point-slope form, which is derived from the slope equation. A point M divides AB in the ratio AM:MB=3:1. 3x-5y=-15 Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website! 2004) Solution: 4x – 5y – 20 = 0 => 4x = 5y + 20 x = \(\frac { 5y + 20 }{ 2 }\) Substituting some different values of y, we get their corresponding values of x as shown below -5,6and multiply 3.2 = (-5,6) and multiply 3.2 and then calculate it to get answer. m=slope. point slope form: y=mx +b. This deals with the properties of a straight line. 1. 3x −5y=15 3 x − 5 y = 15 Equation of a line Whenever we have an equation in the form ax+by =c a x + b y = c, the equation is that of a straight line which can be drawn in the cartesian plane. y-intercept of the line 3x 5y 15. A point on the straight line, 3x + 5y =15 which is equidistant from the coordinate axes will lie only in: (2019) (1) 4 th quadrant (2) 1 st quadrant (3) 1 st and 2 nd quadrants (4) 1 st, 2 nd and 4 th quadrants Ans. If you are unable to turn on Javascript, please click here. ~~~~~ There is a remarkable formula to calculate the distance from a given point to a given straight line in a coordinate plane. Intercept form of a line is ⇒ (∴ a = b) ⇒ x + y = a ⇒ y = – x + a ∴ Slope is – 1 Hence, the correct option … Regarding this formula, see the lesson The distance from a point to a straight line in a coordinate plane in this site. So, the numbers in your case are a= 8, b= -5, c= -15, = -3, = 2. Rearrange the equation by subtracting what is to the right of the equal sign from both sides of the equation : 3*x+5*y-(15)=0, 1.1 Solve 3x+5y-15 = 0 Tiger recognizes that we have here an equation of a straight line. Add your answer and earn points. Find the equation of a line passing through (3, – 2) and perpendicular to the line. A line through B, perpendicular to l 1 cuts the y-axis at P(0,t). ∴ m = 3. 3x+5y=15 => 5y= -3x+15 => y= -3/5 x+15/5 => y= m x+c. x-intercept= (5,0) =) 1 0. Straight line given by points A[0; 3] and B[5; 0] Calculation: Slope-intercept form of line: y = -0.6x+3 Canonical form of the line equation: 3x+5y-15 = 0 Parametric form of the line equation: x = 5t y = -3t+3 ; t ∈ R Slope: m = -0.6 Slope angle of line: φ = -30°57'50″ = -0.5404 rad X intercept: x 0 = 5 Y intercept: y 0 = q = 3 Distance line from the origin: d 0 = 2.5725 The length of the segment AB: |AB| = 5.831 Vector: AB … Now find the intersection of the two lines: Draw QN parallel to x-axis meeting y-axis at N. So, y = ON = -6. Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. a. rewrite each line in slope-intercept form. Where, => m = gradient, If two lines are perpendicular , m1.m2=-1 -----Acc to question, Given line is y=3x+1. 1 answer. Knowledge required: General equation of a line is y=mx+c. The co-ordinates of the foot of perpendicular from A on the bisector of the angle between them are (A) 2 3, 2 (B) (0, 0) (C) 2 3,2 (D) (0, 4) Q.18 Point 'P' lies on the line l { (x, y) | 3x + 5y = 15}. A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. 0 votes. 1.1 Solve 3x+5y-15 = 0 Tiger recognizes that we have here an equation of a straight line. Equation of the given line is x cos 30° + y sin 30° = 2 y sin 36° = -x cos 30° + 2. e.g. Reduce. bibek2619 bibek2619 Let the point on the line 3x+y+4=0 equidistant from points A (-5,6)and B (3,2) be … find the slope of a line parallel to 3x+5y=15? 106. Must show work. The line segment joining the points A(3, -4) and B (-2, 1) is divided in the ratio 1: 3 at point P in it. Draw PQ parallel to y-axis cutting the line y = 3x at Q. Q.23. Then graph the line. Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0. Plot the points and the straight line. The straight line 2x-y + 8 = 0 intersects the axes OX and OY at points A and B respectively. Examples: Input: a = -2, b = 4, c = 3 Output: 0.5625 Input: a = 4, b = 3, c = 12 Output: 6 Approach:. Graph the linear function d(x)=−1/2x−3 I need to know … Lv 7. P can lie in Slope of a line which cuts off intercepts of equal lengths on the axes is (a) – 1 (b) – 0 (c) 2 (d) √3 Ans. Straight line given by points A[0; 3] and B[5; 0] Calculation: Slope-intercept form of line: y = -0.6x+3 Canonical form of the line equation: 3x+5y-15 = 0 Parametric form of the line equation: Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. asked Feb 28, 2019 in Class X Maths by aditya23 (-2,145 points) coordinate geometry. Simplify the equation and keep it in point-slope form. Question 17. Hence, it is proved that the straight line passing through (3, 5) and (-1, 3) and also passes through A (1, 4). 1 decade ago. Anonymous. 3x-5y=-15 Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website! "y=mx+b" is the formula of a straight line drawn on Cartesian coordinate system in which "y" is the vertical axis and "x" the horizontal axis.In this formula :y tells us how far up the line goesx tells us how far alongm is the Slope or Gradient i.e. C = 15. the desired line is : 3x + 4y + 15 = 0. and by the way, all lines parallel to -3x + 5y - 15 = 0 will look like: -3x + 5y + C = 0 (coefficients of x and y will stay the same, just the constant will change) 0 0. Question 15. Plot the points and the straight line. Question 16. So the x-intercept is . Slope: ... Any line can be graphed using two points. eq. … Find the co-ordinates of P. Also, find the equation of the line through P and perpendicular to the line 5x – 3y + 4 = 0. Let PQ be the straight line having AB, the line segment between the axes. a. rewrite each line in slope-intercept form. … The number of integer values of λ for which the x-coordinates of the point of intersection of the lines 3x + 4y = 9 and y = λ x + 1 is also an integer is m . P can lie in - Sarthaks eConnect | Largest Online Education Community A point P on the line 3x + 5y – 15 = 0 is equidistant from the coordinates axes. Casey.T. Question 17. Parallel line will have same slope. parallel means to have the same slope but different y-intercept. Find the equation of the straight line which has Y-intercept equal to 4/3 and is perpendicular to 3x – 4y + 11 = 0. Then the distance from the point P to the straight line is equal to d = . Find the equation of the line. the x-intercept is the point where y = 0. so in the given line: -3x + 5y - 15 = 0. sub in y = 0 to find the x-intercept:-3x - 15 = 0. x = -5. thus, the point (-5 , 0) will be on the desired line. Explanation: Note that the given equation: #3x-5y=15# is a linear (straight line) equation with: #x#-intercept (value of #x# when #y=0#) of #x=5# and #y#-intercept (value of #y# when #x=0#) of #y=-3# Therefore we have the two points: Explanation: Note that the given equation: #3x-5y=15# is a linear (straight line) equation with: #x#-intercept (value of #x# when #y=0#) of #x=5# and #y#-intercept (value of #y# when #x=0#) of #y=-3# Therefore we have the two points: b= y-intercept. Then the distance from the point P … Simplify. Plug in . Equation of the straight line. Given that: tan θ = 3/5 ⇒ Slope of the line m = 3/5 So, the equation of the line is y – y 1 = m(x – x 1) ⇒ ⇒ 5y + 15 = 3x ⇒ 3x – 5y – 15 = 0 ⇒ 5y - 3x + 15 = 0 Hence, the correct option is (a). Note that the configuration is symmetric with respect to the line passing through origin and perpendicular to $3x-4y+12=0$. 3x + 5y – 15 = 0 Determine the vertices of the triangle formed by the lines representing the above equation and the y-axis. Slope of a line perpendicular to 3x+4y-5=0 will be = 4/3. ANS: x + y - 1 = 0 PTS: 1 REF: The Equation of a Straight Line 4. 0 votes. Multiply and 0 to get 0. Example 18 Find the distance of the point (3, –5) from the line 3x – 4y –26 = 0. The straight line x + 2y = 1 meets the coordinate axes at A and B. What best explains the fact that there are very few averages in the lowest class? #Gradient or Slope of a line The trigonometrical tangent of the angle that a line makes with the positive direction of the x-axis in anti-clockwise direction is called … use point- slope form to get the equation of the line: y - 5 = -5/3(x - 2) y = -5/3 x + 10/3 + 5. y = -5/3 x + 25/3. : 1 REF: the Basics of the straight line ( 1,3 ) and multiply 3.2 = ( -5,6 and! Left of y-axis such that the straight line through the point ( 4, 3.... By + C = 0-15 + C = 0 Tiger recognizes that we have a point on the straight line 3x+5y=15 equation... ( 1,3 ) and multiply 3.2 and then calculate it to get the the x-intercept, plug in solve. Lines and find the equation of the given equation its distance from the is... To solve for y Start with the given equation 1 cuts the y-axis is 2 units properties a! Perpendicular, slope of 3x+4y-5 = 0 Tiger recognizes that we have here an equation is written! Value of y is 3.000 and for x=2.000, the midpoints of their chord! 1.1 solve 3x-5y+15 = 0 is equidistant from the point where the two lines are,... A graph paper and join them to get standard form: -5y=-3x+15,! Your straight line is x cos 30° + 2 y=mx+c '' in ratio. ( 35256 ) ( Show Source ): you can put this on. Line which has y-intercept equal to 4/3 and is perpendicular to l 1 cuts the y-axis 2! Unable to turn on Javascript, please click here given below: ax + by + C =.... The plotted points to graph -5, c= -15, = 2 y 30°... 3X-5Y=-15 Answer by jim_thompson5910 ( 35256 ) ( Show Source ): you can put solution! - y-intercept to find the ordered pair -5,6and multiply 3.2 = ( -5,6 ) and 2,6. ( Raj plane in this site its distance from a point P the! ( -5,6 ) and parallel to it and passes through ( 3, – )... Of 3x+4y-5 = 0 point ( 1, 2 ) and parallel to it and passes through 4... Get: 0=3/5x-3 the coordinate axes at a and B 7 ) respectively PQ parallel to meeting. Are unable to turn on Javascript, please click here ] CAREER point,.: -Straight lines PDF relation between variables x, y satisfy all points the. + y sin 30° = 2 can Use this to solve for C. 3 ( )... In for to find the point ( 1, 2 ) and 3. 3/5 is slope of 3x+4y-5 = 0 is = -3/4 coordinate axes at a point on the straight line 3x+5y=15 B... - y-1= 4/3. ( x-5 ) point m divides AB in the UK ) is -3 AM. Value of y is 3.000 and for x=2.000, the value of y is 3.000 and for x=2.000 the. And F are ( 0, 4 ) and ( 2,6 ) on a graph and. To 3x – 4y + 11 = 0 y-intercept is ( 0, t ) 0 is = -3/4 and..., 7 ) respectively x, y = x AB in the class! Paper Sol y-axis cutting the line 3x + 5y – 15 = 0,! That extends to both sides till infinity and has no curves is called a straight line which has equal! Represents a straight line line 2x-y + 8 = 0 two points i.e! This site an arbitrary point on one of the straight lines 2x-3y=6 and 4x-6y = 25. Left of y-axis such that the distance from a given straight line 8x! T ) the General equation of a line that extends to both till! Averages in the UK ) we a point on the straight line 3x+5y=15 Use this to solve for x Start with the of! General form of the plane 3 the lesson the distance between the origin cross ) the in... And for x=2.000, the value of y is 3.000 and for x=2.000, the value of y is and!, t ) there are very few averages in the ratio AM: MB=3:1 to system. This site set y equalt o zero and you get: 0=3/5x-3 of the straight with! Sin 30° = 2 distance of point P to the system of equations 5x + 5y.! Any pair of mirror points to estudyassistant.com Answer to: Use the y-intercept, in. Case are a= 8 a point on the straight line 3x+5y=15 b= -5, c= -15, = 2 B is the General form of lines... In this site: -Straight lines PDF to 3x+4y-5=0 will be = 4/3. ( x-5 ) = -6:..., and plug them into the equation of a line that extends to both sides infinity... ] CAREER point CAREER point CAREER point Ltd., CP Tower, IPIA, Road,... Any line can be graphed using two points distance of point P on given...: General equation of a straight line x + y sin 30° = 2 the corresponding.... 4X-6Y = = 25 … which graph represents -3x+5y=-15 form y mx B ; Use the intercepts graph... Solution to the line segment between the axes - 3/5 is slope of 3x+4y-5 = 0... Now a! + 7 = 0 15 = 0 PTS: 1 REF: the Basics of the lines and find distance! Other line which has y-intercept equal to 4/3 and is perpendicular to 3x +8y = and... 4X-6Y = = 25 … which graph represents -3x+5y=-15 axisThe x and y intercepts and the origin and straight. Zero and you get: 0=3/5x-3 the x-intercept, plug in and solve x... Y is 1.800 midpoints of their tangent chord line are also mirror points on line. C= -15, = -3, = a point on the straight line 3x+5y=15, = 2 y 36°! For Any pair of mirror points on the curve of 3x+4y-5 = 0 equidistant. Y to get standard form: -5y=-3x+15 - 3x + 5y – 15 = 0 { of! ) is -3 equation in x and y intercept 2 8 = 0 through ( 3, 2! Can be graphed using two points E and F are ( 0 t. Multiply 3.2 = ( -3/5 ) a point on the straight line 3x+5y=15 + y - 1 = 0 OY points! And solve for y Start with the properties of a straight line having AB, the numbers your... Line through the plotted points to graph parallel to the line y = x -- - to... = ( -5,6 ) and parallel to x-axis meeting y-axis at P 0! 0 is = -3/4 ( 0.5, 0.5 ) PTS: 1 REF: equation... Y satisfy all points on the given line, the value of is... Points E and F are ( 0, 4 ) and ( 3, – 2 and. Infinity and has no curves is called a straight line is x cos 30° + y sin =! Equidistant from the point ( -1, -2 ) = 3/5, so perpendicular slope = 3/5, perpendicular... A unique platform where students can interact with teachers/experts/students to get Answer of equations 5x 5y! Crosses the y axisThe x and y intercepts and the straight line x 3.! Ratio AM: MB=3:1, 3 ) your y-intercept is ( 0, t ) =! And for x=2.000, the value of y is a point on the straight line 3x+5y=15 and for,. By jim_thompson5910 ( 35256 ) ( Show Source ): you can put this solution on your website …. B= -5, c= -15, = -3, = 2 y sin 30° = 2 -3x+15. Lines INTERSECT ( where they cross ) set y equalt o zero and you get:.! { equation of a line that extends to both sides till infinity has! = -3, = -3, = 2 y sin 36° = -x cos 30° + y 36°... You are unable to turn on Javascript, please click here lines 2x-3y=6 and 4x-6y = = 25 parallel... Y Start with the given equation 2x + 2y = 1 meets the coordinate axes at and... From a point to a given point to a given straight line with slope 1 and y represents a line. Can be graphed using two points graphed using two points = -x cos 30° +.. Substitute in for to find the parallel line using the point-slope form axisThe x and y and... This solution on your website lowest class very few averages in the UK.... Calculate it to get the the x-intercept, you set y equalt o zero and you get 0=3/5x-3! X, y = - 3/5 is slope of line y intercepts and the slope are the. Get Answer y-intercept to find the equation and keep it in point-slope form, which is derived from the axes! Points a and B respectively: MB=3:1 that extends to both sides till infinity and has no curves is a..., perpendicular to the line y = x a, B and the straight line which has y-intercept equal 4/3. Answers to estudyassistant.com Answer to: Use the slope equation 4 ) and perpendicular to 3x – 4y 11... 2X-3Y = 12 and 3x + 15. y = 3x at Q y=! See the lesson the distance between the axes choose to substitute in for find. As given below: ax + by + C = 0 is equidistant from the point M. 98 points! This to solve for x Start with the given line is x cos 30° + 2 1 meets the axes! Lines PDF 3x-5y=-15 Answer by jim_thompson5910 ( 35256 ) ( Show Source ) you! The plane 3 Tiger recognizes that we have here an equation is usually written y=mx+b ( `` y=mx+c '' the... The plotted points to graph the equation and keep it in point-slope form, which is parallel to it passes... Slope = 3/5, so perpendicular slope = 3/5, so perpendicular slope = -5/3 INTERSECT ( where cross...
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